EE 2260 Lecture 18 Fourier Transform Reading: 17.1 – 17.3 HW #18 AP: 17.1, 17.2, 17.3 §17.1 The Derivation of the Fourier Transform For a periodic function f(t) we have a Fourier series: or in the exponential form: If the function f(t) is not periodic, we may think that the period T   . In this situation,  1 d  jt dt  , n0   , C n T   f (t )e T 2  We define the Fourier transform of f(t) as F ( )    f (t )e  jt dt  The Fourier expansion becomes the Inverse Fourier transform: 1 f ( t )  jn0t 1 f ( t )   (C n T ) e  2 T n      F ( )e j t d  Example1: Example2: f (t )  e  at u(t ) , a > 0. F ( )  PLOTS    0  at  jt  ( a  j ) t dt   e u(t )e dt   e e  ( a  j ) t  1 |0   ( a  j ) a  j . . §17.2 The Convergence of the Fourier Integral We consider some useful but not integrable functions. Example:  Find the Fourier transform of a constant f(t) = 1: 1 e  jt  dt   e   jt e  jt  dt  |   ?  j Let’s consider a different function: f (t )  e  a |t | , a > 0. F ( )    a|t|  jt  e e dt   0   0 at  jt  at  jt  e e dt   e e dt  1 1 2a   2 a  j a  j a   2 2a 0 a  2 2a If   0 , let a  0 , 2   a If   0 , let a  0 , 2 Notice that the area under the curve (not shown)  2a x 2a is d  2 tan 1 |  2  2 2 2 2 a a   a   Therefore, F ( )  2 ( ) when f(t) = 1. §17.3 Using Laplace Transforms to Find Fourier Transforms Case #1: f(t) = 0 for t < 0 and let s =j. Example: f (t )  e  at cos(0 t )u(t ) , Case #2: f(t) = 0 for t > 0 and let s = -j. F ( )     f (t )e  jt dt  0   f (t )e  jt dt  Change f(t) to f(-t), and let s = -j.  jt  f ( t )e dt 0 Example: f ( t )  e at cos(  0 t )[ 1  u ( t )] , f ( t )  e  at cos(0 t )[1  u( t )]  e at cos(0 t )u(t ) Case #3: For a general f (t )  f  (t )  f  (t ) , where f  (t )  f (t )u(t ) , f  (t )  f (t )[1  u(t )] Example: f (t )  e  a|t|  e  at u(t )  e at [1  u(t )] , f  (t )  e  at u(t ) , f  ( t )  e  at u(t )
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