Homework 3, Sannolikhetsteori Alex Loiko 910620-1719 Masterprogrammet datalogi, åk. 1 26 oktober 2014 Difference of Exp(1)-distributed values is L(1)-distributed Show, by using moment generating functions, that if X ∈ L(1), d then X = Y1 − Y2 , where Y1 , Y2 ∈ Exp(1) are independent. If Y1 , Y2 are independent, then Y1 , −Y2 are also independent. The MGF of Y1 is Z ∞ ψY1 (t) = ety fY (y)dy = 0 Z ∞ 1 (t−1)y ∞ (t−1)y e dy = e = t−1 0 0 1 1 0− = t−1 1−t 1 for t < 1. The MGF of −Y2 is then 1+t . By Theorem 3.2, MGF of sum 1 of random variables, the MGF of Y1 + (−Y2 ) is 1−t 2. The MGF of a Laplace-distributed s.v. Z ∈ L(1) is Z ∞ ty 1 −|y| e e dy = 2 −∞ Z 1 ∞ ty−|y| e dy = 2 −∞ ! 1 1 0 1 ∞ + = 2 t + 1 −∞ t−1 0 1 1 1 1 + = 2 t+1 1−t 1 − t2 1 By Theorem 3.1, equal MGFs imply equal distributions Y1 − Y1 ∈ L(1) and the proof is done. 2
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