Chapter 19: Two-Factor Studies with Equal Sample Size Lecture 13 April 3, 2007 Psych 791 Slide 1 of 36 Seen Previously ■ Overview Last Thursday we talked about: ◆ How the 2-way ANOVA model is: ● Previous Class ● Today’s Class ■ Formulated. ■ Estimated. ■ How significant effects are determined. Testing Effects Strategy for Analysis Estimating Means Multiple Comparisons Interaction Data Example Wrapping Up Slide 2 of 36 Today’s Class Overview ● Previous Class ● Today’s Class ■ Today, we are going to go one step further. ■ How do we determine where the differences are once we have determined that there are significant effects. Testing Effects Strategy for Analysis Estimating Means Multiple Comparisons Interaction Data Example Wrapping Up Slide 3 of 36 Testing Effects Slide 4 of 36 Testing for Main Effect of A ■ Null Hypothesis: Overview H0 : α1 = α2 = . . . = αa = 0 Testing Effects ● Testing for Main Effect of A ● Testing for Main Effect of B ● Testing for Interaction Effect of A × B Ha : not all αi = 0 ● Family of Significance Strategy for Analysis ■ or alternatively: Estimating Means Multiple Comparisons H0 : µ1· = µ2· = . . . = µa· Interaction Data Example Ha : not all µi· equal Wrapping Up ■ To test: M SA F (a − 1, ab(n − 1)) = M SE Slide 5 of 36 Testing for Main Effect of B ■ Null Hypothesis: Overview H0 : β1 = β2 = . . . = βb = 0 Testing Effects ● Testing for Main Effect of A ● Testing for Main Effect of B ● Testing for Interaction Effect of A × B Ha : not all βj = 0 ● Family of Significance Strategy for Analysis ■ or alternatively: Estimating Means Multiple Comparisons H0 : µ·1 = µ·2 = . . . = µ·b Interaction Data Example Ha : not all µ·j equal Wrapping Up ■ To test: M SB F (b − 1, ab(n − 1)) = M SE Slide 6 of 36 Testing for Interaction Effect of A × B ■ Null Hypothesis: Overview H0 : all (αβ)ij = 0 Testing Effects ● Testing for Main Effect of A ● Testing for Main Effect of B ● Testing for Interaction Effect of A × B Ha : not all (αβ)ij = 0 ● Family of Significance Strategy for Analysis ■ or alternatively: Estimating Means Multiple Comparisons H0 : all µij equal Interaction Data Example Ha : not all µij equal Wrapping Up ■ To test: F ((a − 1)(b − 1), ab(n − 1)) = M SAB M SE Slide 7 of 36 Family of Significance ■ The Bonferroni inequality was a way of controlling our alpha level. ■ So, if we have three significance tests (both main effects and interaction), each at an alpha level of 0.05, then our total α according to Bonferroni is: α ≤ α1 + α2 + α3 .15 ≤ .05 + .05 + .05 ■ A second way of looking at this is called the Kimball inequality. ■ This takes into account that the SSE is in each test statistic (common denominator): α ≤ 1 − (1 − α1 )(1 − α2 )(1 − α3 ) .143 ≤ 1 − (.95)(.95)(.95) Slide 8 of 36 Strategy for Analysis ■ There are 6 steps that you should follow when analyzing two factor studies: 1. Examine whether the two factors interact. 2. If they do not interact, examine whether the main effects for both factors (A and/or B) are important. If important, describe the nature of the effects. 3. If they do interact, examine if the interactions are important. 4. If they are unimportant, proceed to step 2. 5. If they are important, can they be made unimportant by a transformation? If so, go to step 2. 6. For important interactions (irrespective of scale), examine the two factors jointly (or the nature of the interaction. Slide 9 of 36 Factor Level Means µi· or µ·j Overview ■ Estimate them by changing µ to Y Testing Effects µi· = Y¯i·· Strategy for Analysis Estimating Means ● Factor Level Means ● Contrasts µ·j = Y¯·j· ● Contrasts, the other way ● Linear Combinations Multiple Comparisons ■ Interaction Data Example Variance now are not simply σ 2 2 σ M SE σ (Y¯i·· ) = = bn bn 2 Wrapping Up 2 σ M SE = σ (Y¯·j· ) = an an 2 ■ Usual confidence intervals can be constructed: test statistic is t with (n − 1)abdf . Slide 10 of 36 Contrast in Factor Level Means ■ You can estimate a contrast, or difference in factor level means for Factor A Overview Testing Effects L= Strategy for Analysis X ci µi· where X ci = 0 Estimating Means ● Factor Level Means ● Contrasts ■ Estimate it by substituting Y ● Contrasts, the other way ● Linear Combinations L= Multiple Comparisons X ci Y¯i·· Interaction Data Example ■ The variance of this contrast is then: Wrapping Up 2 X σ M SE X 2 b σ (L) = ci = ci bn bn Slide 11 of 36 Contrasts, the other way ■ Again, you can estimate a contrast, or difference in factor level means, for Factor B Overview Testing Effects L= Strategy for Analysis X cj µ·j where X cj = 0 Estimating Means ● Factor Level Means ● Contrasts ■ Estimate it by substituting Y ● Contrasts, the other way ● Linear Combinations L= Multiple Comparisons X cj Y¯·j· Interaction Data Example ■ The variance of this contrast is then: Wrapping Up 2 X σ M SE X 2 b σ (L) = cj = cj an an Slide 12 of 36 Linear Combinations Overview Testing Effects ■ This is a "contrast" where the c’s sum to 1 instead of 0. ■ Estimate these in the same way as the previous 2 slides, same estimates, same variances. Strategy for Analysis Estimating Means ● Factor Level Means ● Contrasts ● Contrasts, the other way ● Linear Combinations Multiple Comparisons Interaction Data Example Wrapping Up Slide 13 of 36 Multiple Comparison Procedures ■ Usually, you don’t want to look at one or two mean differences, you want to look at all of them at the same time. ■ We can employ the same multiple comparison procedures used in single factor studies (Tukey, Bonferroni, Scheffé), with minor tweaking. Overview Testing Effects Strategy for Analysis Estimating Means Multiple Comparisons ● Tukey ● Bonferroni ● Both A and B ● Multiple Contrasts - Scheffé ● Multiple Contrasts Bonferroni ● Both Factor A and B Interaction Data Example Wrapping Up Slide 14 of 36 Tukey ■ We have the same test for difference (for Factor A as an example): Overview Testing Effects D = µi· − µi′ · Strategy for Analysis Estimating Means ■ Multiple Comparisons We have the same confidence interval: ● Tukey ● Bonferroni b ± t(1 − α/2; nT − r) ∗ s(D) b D ● Both A and B ● Multiple Contrasts - Scheffé ● Multiple Contrasts Bonferroni ● Both Factor A and B Interaction ■ But two things change, the standard deviation and the test statistic: Data Example Wrapping Up 1 T = √ q(1 − α; a, (n − 1)ab) 2 2M SE b s (D) = bn 2 Slide 15 of 36 Bonferroni ■ Use the same formulas as above for difference and standard deviation, but replace T with B: Overview Testing Effects Strategy for Analysis B = t(1 − α/2g; (n − 1)ab) Estimating Means Multiple Comparisons ● Tukey ● Bonferroni ● Both A and B ● Multiple Contrasts - Scheffé ● Multiple Contrasts Bonferroni ● Both Factor A and B Interaction Data Example Wrapping Up Slide 16 of 36 Both A and B ■ Both the Tukey and the Bonferroni method look at the effects of a single factor. ■ If both are significant, we will probably want to perform multiple comparison procedures on both of these effects. ■ You can do this in two ways: Overview Testing Effects Strategy for Analysis Estimating Means Multiple Comparisons ● Tukey ● Bonferroni ● Both A and B ● Multiple Contrasts - Scheffé ● Multiple Contrasts - 1. Use the Bonferroni method, where g is ALL the differences for both factors. Bonferroni ● Both Factor A and B Interaction Data Example Wrapping Up 2. Use both Bonferroni and Tukey: calculate a Bonferroni for the number of factors you want to test, then run a Tukey using that Bonferroni (basically if you estimate 2 effects, use an α = 0.025 for the Tukey test). Slide 17 of 36 Multiple Contrasts - Scheffé b ± S ∗ s(L) b L Overview ■ For analyzing multiple contrasts in two factor studies, we define S as follows. ■ For the A factor: Testing Effects Strategy for Analysis Estimating Means p S = (a − 1)F (1 − α; a − 1, (n − 1)ab) Multiple Comparisons ● Tukey ● Bonferroni ● Both A and B ● Multiple Contrasts - Scheffé ● Multiple Contrasts Bonferroni ● Both Factor A and B Interaction Data Example ■ For the B factor: p S = (b − 1)F (1 − α; b − 1, (n − 1)ab) Wrapping Up Slide 18 of 36 Multiple Contrasts - Bonferroni ■ Insert a B for the S in the previous formula. b ± B ∗ s(L) b L Overview Testing Effects Strategy for Analysis ■ Estimating Means Multiple Comparisons ● Tukey ● Bonferroni ● Both A and B Define B as: B = t(1 − α/2g; (n − 1)ab) ● Multiple Contrasts - Scheffé ● Multiple Contrasts Bonferroni ● Both Factor A and B Interaction Data Example Wrapping Up Slide 19 of 36 Both Factor A and B ■ When using multiple contrasts involving both factors at the same time, we still want to control our total error. ■ There are three possibilities in this case: Overview Testing Effects Strategy for Analysis Estimating Means Multiple Comparisons 1. Use the Bonferroni method, changing g to the total number of contrasts. ● Tukey ● Bonferroni ● Both A and B 2. Use Bonferroni for the total α for more than one Scheffé. ● Multiple Contrasts - Scheffé ● Multiple Contrasts Bonferroni ● Both Factor A and B Interaction Data Example 3. Change the S in Scheffé to: p S = (a + b − 2)F (1 − α; a + b − 2, (n − 1)ab) Wrapping Up Slide 20 of 36 Important Interaction Overview ■ Each of the above tests are for factor level means. ■ Let us go back to the idea of an important interaction. ■ Suppose we find a significant interaction that we deem important, what do we do next? ■ It would be nice to have some way to test differences in the treatment means. Testing Effects Strategy for Analysis Estimating Means Multiple Comparisons Interaction ● Important Interaction ● Tukey ● Bonferroni ● Multiple Treatment Contrasts ● Scheffé ● Bonferroni Data Example Wrapping Up Slide 21 of 36 Multiple Comparisons - Treatment ■ We are just going to extend this idea of multiple pairwise comparisons to treatment means. ■ We are going to look at all possible pairwise µij or subsets of the pairs. Overview Testing Effects Strategy for Analysis Estimating Means D = µij − µi′ j ′ Multiple Comparisons Interaction ● Important Interaction ● Tukey ● Bonferroni ● Multiple Treatment Contrasts ● Scheffé ■ Using this new difference estimate, we can now use either Tukey or Bonferroni’s method on these treatment means. ● Bonferroni Data Example Wrapping Up Slide 22 of 36 Tukey b ± T ∗ s(D) b D Overview b = 2M SE s2 (D) n Testing Effects Strategy for Analysis Estimating Means ■ Then we just need to define our T: Multiple Comparisons Interaction ● Important Interaction ● Tukey ● Bonferroni 1 √ q(1 − α; ab, (n − 1)ab) T = 2 ● Multiple Treatment Contrasts ● Scheffé ● Bonferroni Data Example Wrapping Up Slide 23 of 36 Bonferroni b ± B ∗ s(D) b D Overview b = s(D) Testing Effects Strategy for Analysis Estimating Means ■ 2M SE n Then we just need to define our B: Multiple Comparisons Interaction ● Important Interaction ● Tukey B = t(1 − α/2g; (n − 1)ab) ● Bonferroni ● Multiple Treatment Contrasts ● Scheffé ● Bonferroni Data Example Wrapping Up Slide 24 of 36 Multiple Treatment Contrasts Overview ■ We may want to look at contrasts for treatment effects. ■ These contrasts would then be of the form: Testing Effects L= Strategy for Analysis X cij µij where X cij = 0 Estimating Means Multiple Comparisons ■ Interaction ● Important Interaction ● Tukey The same idea is employed, just with slightly different methods. ● Bonferroni ● Multiple Treatment Contrasts ● Scheffé ● Bonferroni Data Example Wrapping Up Slide 25 of 36 Scheffé ■ Multiple Contrasts can be estimated using Scheffé’s method: b ± S ∗ s(L) b L Overview Testing Effects Strategy for Analysis XX M SE b = s (L) c2ij n 2 Estimating Means Multiple Comparisons Interaction ● Important Interaction ● Tukey ● Bonferroni ■ For analyzing multiple contrasts in two factor studies for the interaction term, we define S as follows: ● Multiple Treatment Contrasts ● Scheffé ● Bonferroni Data Example p S = (ab − 1)F (1 − α; ab − 1, (n − 1)ab) Wrapping Up Slide 26 of 36 Bonferroni ■ Overview B = t(1 − α/2g; (n − 1)ab) Testing Effects Strategy for Analysis ■ Estimating Means Multiple Comparisons Same as on previous slide, but replace S with B: Just as in single factor studies, Bonferroni is preferred when the number of contrasts is small. Interaction ● Important Interaction ● Tukey ● Bonferroni ● Multiple Treatment Contrasts ● Scheffé ● Bonferroni Data Example Wrapping Up Slide 27 of 36 Putting It All Together ■ The primary objective of the Study on the Efficacy of Nosocomial Infection Control (SENIC Project) was to determine whether infection surveillance and control programs have reduced the rates of nosocomial (hospital-acquired) infection in the United States. 113 subjects were studied in this sample. ■ Research Question: The researchers are interested in determining if medical school affiliation and region of the country are related to infection risk. Overview Testing Effects Strategy for Analysis Estimating Means Multiple Comparisons Interaction Data Example ● Putting It All Together ● SAS Code - Step 1 ● Output - Step 1 ● SAS Code - Step 2 ● Output - Step 2 ● SAS code - test differences ● Output - test differences Wrapping Up Slide 28 of 36 SAS Code - Step 1 Overview Testing Effects Strategy for Analysis data senic; infile ’path\senicex1.csv’ dlm=’,’; input id infrisk medaff region; run; Estimating Means Multiple Comparisons Interaction Data Example ● Putting It All Together proc glm data=senic; class medaff region; model infrisk = medaff|region; run; ● SAS Code - Step 1 ● Output - Step 1 ● SAS Code - Step 2 ● Output - Step 2 ● SAS code - test differences ● Output - test differences Wrapping Up Slide 29 of 36 Output - Step 1 Dependent Variable: infrisk DF Sum of Squares Mean Square F Value Pr > F Model 7 30.1153614 4.3021945 2.64 0.0150 Error 105 171.2644616 1.6310901 Corrected Total 112 201.3798230 Source Overview Testing Effects Strategy for Analysis Estimating Means Multiple Comparisons R-Square Coeff Var Root MSE infrisk Mean 0.149545 29.32676 1.277141 4.354867 Interaction Data Example ● Putting It All Together ● SAS Code - Step 1 ● Output - Step 1 Source DF Type I SS Mean Square F Value Pr > F 1 3 3 10.93551541 11.64824242 7.53160355 10.93551541 3.88274747 2.51053452 6.70 2.38 1.54 0.0110 0.0738 0.2087 DF Type III SS Mean Square F Value Pr > F 1 3 3 7.61386560 5.38396032 7.53160355 7.61386560 1.79465344 2.51053452 4.67 1.10 1.54 0.0330 0.3525 0.2087 ● SAS Code - Step 2 ● Output - Step 2 ● SAS code - test differences ● Output - test differences medaff region medaff*region Wrapping Up Source medaff region medaff*region Slide 30 of 36 SAS Code - Step 2 Overview Testing Effects proc glm data=senic; class medaff region; model infrisk = medaff region; run; Strategy for Analysis Estimating Means Multiple Comparisons Interaction Data Example ● Putting It All Together ● SAS Code - Step 1 ● Output - Step 1 ● SAS Code - Step 2 ● Output - Step 2 ● SAS code - test differences ● Output - test differences Wrapping Up Slide 31 of 36 Output - Step 2 Dependent Variable: infrisk DF Sum of Squares Mean Square F Value Pr > F Model 4 22.5837578 5.6459395 3.41 0.0115 Error 108 178.7960652 1.6555191 Corrected Total 112 201.3798230 Source Overview Testing Effects Strategy for Analysis Estimating Means Multiple Comparisons R-Square Coeff Var Root MSE infrisk Mean 0.112145 29.54556 1.286670 4.354867 Interaction Data Example ● Putting It All Together ● SAS Code - Step 1 ● Output - Step 1 Source DF Type I SS Mean Square F Value Pr > F medaff region 1 3 10.93551541 11.64824242 10.93551541 3.88274747 6.61 2.35 0.0115 0.0769 Source DF Type III SS Mean Square F Value Pr > F medaff region 1 3 8.58681851 11.64824242 8.58681851 3.88274747 5.19 2.35 0.0247 0.0769 ● SAS Code - Step 2 ● Output - Step 2 ● SAS code - test differences ● Output - test differences Wrapping Up Slide 32 of 36 SAS code - test differences Overview Testing Effects Strategy for Analysis proc glm data=senic; class medaff region; model infrisk = medaff region; lsmeans medaff/tdiff adjust=tukey; run; Estimating Means Multiple Comparisons Interaction Data Example ● Putting It All Together ● SAS Code - Step 1 ● Output - Step 1 ● SAS Code - Step 2 ● Output - Step 2 ● SAS code - test differences ● Output - test differences Wrapping Up Slide 33 of 36 Output - test differences The GLM Procedure Least Squares Means Adjustment for Multiple Comparisons: Tukey-Kramer Overview medaff infrisk LSMEAN H0:LSMean1=LSMean2 t Value Pr > |t| Testing Effects Strategy for Analysis 1 2 5.05375330 4.27289190 2.28 0.0247 Estimating Means Multiple Comparisons Interaction Data Example ● Putting It All Together ● SAS Code - Step 1 ● Output - Step 1 ● SAS Code - Step 2 ● Output - Step 2 ● SAS code - test differences ● Output - test differences Wrapping Up Slide 34 of 36 Final Thought ■ Today we covered the multiple comparisons side of 2-way ANOVA. ■ Everything shown was identical to what happened in 1-way ANOVA. ■ With this we can put Chapter 19 to bed. ■ We will encounter interactions later in the book. Overview Testing Effects Strategy for Analysis Estimating Means Multiple Comparisons Interaction Data Example Wrapping Up ● Final Thought ● Next Class Slide 35 of 36 Next Time ■ Chapter 21 (skip Chapter 20): Randomized Complete Block Designs. Overview Testing Effects Strategy for Analysis Estimating Means Multiple Comparisons Interaction Data Example Wrapping Up ● Final Thought ● Next Class Slide 36 of 36
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